What is the half-reaction that occurs at the cathode during electrolysis of an aqueous potassium iodide solution?
Reduction Half-Reaction
E° (V)
K+(aq) + e-
K(s) -2.93
Mg2+(aq) + 2e-
Mg(s) -2.37
2H2O(l) + 2e-
H2(g) + 2OH-(aq) -0.83
2H+(aq) + 2e-
H2(g) 0.00
I2(s) + 2e-
2I-(aq) 0.54
O2(g) + 4H+(aq) + 4e-
2H2O(l) 1.23
A) H2O(l) → 1/2 O2(g) + 2H+(aq) + 2e-
B) 2H2O(l) + 2e- → H2(g) + 2OH-(aq)
C) K(s) → K+(aq) + e-
D) K+(aq) + e- → K(s)
E) I2(aq) + 2e- → 2I-(aq)
Correct Answer:
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