When Au is obtained by electrolysis from NaAu(CN)₂,what is the minimum number of coulombs required to produce 1.26 mol of gold?

Question

Quizplus · Accepted Answer

The minimum number of coulombs required to produce 1.26 mol of gold can be calculated using Faraday's law of electrolysis, which states that the amount of substance liberated during electrolysis is directly proportional to the quantity of electricity that passes through the electrolyte. Since gold (Au) has a valency of +3, the calculation involves the charge of one mole of electrons (Faraday's constant, approximately $96485 \, \text{C mol}^{-1}$) multiplied by the number of moles of gold and the valency. Thus, $1.26 \, \text{mol} \times 3 \times 96485 \, \text{C mol}^{-1} = 1.22 \times 10^{5} \, \text{C}$, which corresponds to choice B.

When Au Is Obtained by Electrolysis from NaAu(CN)2,what Is the Minimum

When Au Is Obtained by Electrolysis from NaAu(CN)₂,what Is the Minimum