A cart is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 4.0 m/s².What is the magnitude of the cart's displacement during the first 6.0 s of its motion? A) 10 m B) 55 m C) 66 m D) 102 m

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Quizplus · Accepted Answer

The displacement can be calculated using the formula: $ s = ut + \frac{1}{2}at^2 $, where $ u = 5.0 \, \text{m/s} $, $ a = 4.0 \, \text{m/s}^2 $, and $ t = 6.0 \, \text{s} $. Substituting these values gives $ s = 5.0 \times 6.0 + \frac{1}{2} \times 4.0 \times (6.0)^2 = 30 + 72 = 102 \, \text{m} $.

A Cart Is Given an Initial Velocity of 5