When a drag strip vehicle reaches a velocity of 60 m/s,it begins a negative acceleration by releasing a drag chute and applying its brakes.While reducing its velocity back to zero,its acceleration along a straight line path is a constant −6.0 m/s².What displacement does it undergo during this deceleration period? A) 120 m B) 300 m C) 320 m D) 240 m

Question

Quizplus · Accepted Answer

The displacement can be calculated using the kinematic equation: $ v^2 = u^2 + 2as $. Here, $ v = 0 $ m/s, $ u = 60 $ m/s, $ a = -6.0 $ m/s². Solving for $ s $, we get $ s = \frac{(0^2 - 60^2)}{2 \times -6} = 300 $ m.

When a Drag Strip Vehicle Reaches a Velocity of 60