A baseball batter hits an incoming 40 m/s fastball.The ball leaves the bat at 60 m/s after a ball-on-bat contact time of 0.030 s.What is the force exerted on the 0.15 kg baseball?
A) 450 N
B) 250 N
C) 90 N
D) 500 N

Question

Quizplus · Accepted Answer

The force exerted on the baseball can be calculated using the formula F = mΔv/Δt, where m is the mass of the ball, Δv is the change in velocity and Δt is the contact time between the ball and bat. 
Substituting the given values, 
F = (0.15 kg)(60 m/s - 40 m/s)/0.030 s = 500 N. 
Therefore, the answer is choice D - 500 N.

A Baseball Batter Hits an Incoming 40 M/s Fastball