Hector drives a pickup truck horizontally at 15.0 m/s.He is transporting a crate of delicate lead crystal.If the coefficient of static friction between the crate and the truck bed is 0.300,what is the minimum stopping distance for the truck so the crate will not slide?
A) 28.7 m
B) 51.0 m
C) 38.3 m
D) 44.4 m

Question

Quizplus · Accepted Answer

The minimum stopping distance can be calculated using the formula d= v^2/(2μg), where v is the initial velocity (15.0 m/s), μ is the coefficient of static friction (0.300) and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we get d= (15.0 m/s)^2/(2×0.300×9.81 m/s^2) = 38.3 m. Therefore, the best choice is C.

Hector Drives a Pickup Truck Horizontally at 15