A block of mass 5.00 kg rests on a horizontal surface where the coefficient of kinetic friction between the two is 0.200.A string attached to the block is pulled horizontally,resulting in a 3.00 m/s² acceleration by the block.Find the tension in the string.(g = 9.80 m/s²) A) 0.200 N B) 9.80 N C) 19.8 N D) 24.8 N

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Quizplus · Accepted Answer

The tension in the string can be found using the formula T = ma + f_k, where f_k is the kinetic friction force. First, calculate the friction force: f_k = μ_k * m * g = 0.200 * 5.00 kg * 9.80 m/s² = 9.8 N. Then, calculate the tension: T = 5.00 kg * 3.00 m/s² + 9.8 N = 15.0 N + 9.8 N = 24.8 N.

A Block of Mass 5