A rock is thrown straight up with an initial velocity of 30.0 m/s.What maximum height will the rock reach before starting to fall downward? (Acceleration due to gravity is 9.80 m/s². ) A) 9.80 m B) 19.6 m C) 20.4 m D) 45.9 m

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Quizplus · Accepted Answer

The maximum height can be calculated using the formula $ h = \frac{v^2}{2g} $, where $ v = 30.0 \, \text{m/s} $ and $ g = 9.80 \, \text{m/s}^2 $. Substituting the values gives $ h = \frac{30.0^2}{2 \times 9.80} = 45.9 \, \text{m} $.

A Rock Is Thrown Straight Up with an Initial Velocity