Water flows over a section of Niagara Falls at a rate of 1.20 × 10⁶ kg/s and falls 51.0 m.What is the power dissipated by the waterfall? A) 599.76 MW B) 61.2 MW C) 43 MW D) 499.76 MW E) 699.76 MW

Question

Quizplus · Accepted Answer

The power dissipated by the waterfall can be calculated using the formula for gravitational potential energy: Power = m * g * h, where m is the mass flow rate (1.20 × 10^6 kg/s), g is the acceleration due to gravity (9.81 m/s²), and h is the height (51.0 m). Calculating gives Power = 1.20 × 10^6 kg/s * 9.81 m/s² * 51.0 m = 599.76 MW.

Water Flows Over a Section of Niagara Falls at a Rate