A force of 100 N is applied to a 50-kg mass in the direction of motion for a distance of 6.0 m and then the force is increased to 180 N for the next 4.0 m.For the 10 m of travel,how much work is done by the varying force?
A) 1 320 J
B) 1 480 J
C) 66 000 J
D) 26.4 J
E) 1 220 J

Question

A force of 100 N is applied to a 50-kg mass in the direction of motion for a distance of 6.0 m and then the force is increased to 180 N for the next 4.0 m.For the 10 m of travel,how much work is done by the varying force?
A) 1 320 J
B) 1 480 J
C) 66 000 J
D) 26.4 J
E) ​1 220 J

Quizplus · Accepted Answer

The work done by a force is given by the formula:

W = Fdcos(theta)

where F is the force, d is the distance moved, and theta is the angle between the force and the direction of motion.

For the first 6.0 m, the force is 100 N, and the angle between the force and the direction of motion is zero, so the work done is:

W = 100 x 6.0 x cos(0) = 600 J

For the next 4.0 m, the force is increased to 180 N. The angle between the force and the direction of motion is still zero, so the work done is:

W = 180 x 4.0 x cos(0) = 720 J

The total work done for the 10 m of travel is the sum of these two amounts:

W_total = 600 J + 720 J = 1,320 J

Therefore, the best choice is A: 1,320 J.

A Force of 100 N Is Applied to a 50-Kg