The net force acting on a 12.6-kg object is given by F_x = (8 - x)N,where F_x is in newtons and x is in meters.How much work is done on the object as it moves from x = 0 to x = 6 m? A) 64 J B) 30 J C) 28 J D) 24 J

Question

Quizplus · Accepted Answer

The work done on the object as it moves from x = 0 to x = 6 m is equal to the area under the force versus displacement graph.

Using the given force equation, we can find the area:

W = ∫(8-x)dx from x=0 to x=6
W = [8x - (x^2)/2] from x=0 to x=6
W = (8*6 - (6^2)/2) - (8*0 - (0^2)/2)
W = 48 - 0
W = 48 J

Therefore, the correct answer is B) 30 J.

The Net Force Acting on a 12