A simple pendulum,2.00 m in length,is released from rest when the support string is at an angle of 35.0° from the vertical.What is the speed of the suspended mass at the bottom of the swing? (g = 9.80 m/s² and ignore air resistance) A) 0.941 m/s B) 1.88 m/s C) 2.66 m/s D) 1.33 m/s

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The potential energy at the top is converted to kinetic energy at the bottom. Using conservation of energy: mgh = 0.5mv^2. The height h can be found using h = L(1 - cos(θ)). Solving for v gives v = sqrt(2gL(1 - cos(θ))), which results in approximately 2.66 m/s.

A Simple Pendulum,2