A 0.200-kg object is swung in a circular path and in a vertical plane on a 0.500-m length string.If the angular speed at the bottom is 8.00 rad/s,what is the tension in the string when the object is at the bottom of the circle?
A) 8.36 N
B) 10.5 N
C) 16.7 N
D) 6.40 N

Question

Quizplus · Accepted Answer

At the bottom of the circle, the tension in the string is given by:$$T = mg + mv^2/r$$where:* m is the mass of the object* g is the acceleration due to gravity* v is the speed of the object* r is the radius of the circlePlugging in the given values, we get:$$T = (0.200 kg)(9.81 m/s^2) + (0.200 kg)(8.00 rad/s)^2(0.500 m)$$$$T = 8.36 N$$Therefore, the correct answer is A.

A 0200-Kg Object Is Swung in a Circular Path and in in a Vertical