A 0.60-kg rock is swung in a circular path and in a vertical plane on a 0.25-m length string.At the top of the path,the angular speed is 12.0 rad/s.What is the tension in the string at that point?
A) 7.9 N
B) 16 N
C) 22 N
D) 6.5 N

Question

Quizplus · Accepted Answer

The tension in the string at the top of the path is calculated using the formula T = m(v^2/r) - mg, where v = ωr. Substituting the given values, T = 0.60*(12*0.25)^2/0.25 - 0.60*9.8 = 16 N.

A 060-Kg Rock Is Swung in a Circular Path and in in a Vertical