In an isobaric process 5 × 10⁴ J of work is done on a quantity of gas while its volume changes from 2.8 m³ to 1.8 m³.What is the pressure during this process? A) 4.4 × 10⁴ Pa B) 3.8 × 10⁴ Pa C) 5.0 × 10⁴ Pa D) 5.6 × 10⁴ Pa E) 6.2 × 10⁴ Pa

Question

Quizplus · Accepted Answer

In an isobaric process, work done (W) is given by W = PΔV, where P is pressure and ΔV is the change in volume. Here, W = 5 × 10^4 J and ΔV = 2.8 m^3 - 1.8 m^3 = 1.0 m^3. Solving for P gives P = W/ΔV = 5 × 10^4 J / 1.0 m^3 = 5.0 × 10^4 Pa.

In an Isobaric Process 5 × 104 J of Work

In an Isobaric Process 5 × 10⁴ J of Work