During each cycle of operation a refrigerator absorbs 45 cal from the freezer compartment and expels 85 cal to the room.If one cycle occurs every 8.0 s,how many minutes will it take to freeze 500 g of water,initially at 0°C? (L_v = 80 cal/g) A) 800 min B) 4400 min C) 120 min D) 150 min

Question

Quizplus · Accepted Answer

The refrigerator removes 45 cal of heat from the freezer compartment during each cycle. So, the heat removed in 8.0 s is 45 cal. The heat required to freeze 500 g of water at 0°C is 500 g * 80 cal/g = 40,000 cal. The time required to freeze the water is 40,000 cal / (45 cal/8.0 s) = 120 min.

During Each Cycle of Operation a Refrigerator Absorbs 45 Cal