A superconducting wire carries a current of 10⁴ A.Find the magnetic field at a distance of 0.25 m from the wire.(µ₀ = 4π × 10−⁷ T⋅m/A) A) 1.6 × 10−² T B) 2 × 10−³ T C) 8 × 10−³ T D) 3.2 × 10−² T

Question

Quizplus · Accepted Answer

We can use the formula for magnetic field due to a current carrying wire:

B = (µ0/4π) * (I/2πr)

Plugging in the given values, we get:

B = (4π × 10−7 T⋅m/A) * (10^14 A/2π*0.25 m)

B = 8 × 10−3 T = 8 × 10−13 T⋅m/A

Therefore, the magnetic field at a distance of 0.25 m from the wire is 8 × 10−13 T or 8 × 10−13 T⋅m/A, which is closest to option C, 8 × 10−13 T.

A Superconducting Wire Carries a Current of 104 A

A Superconducting Wire Carries a Current of 10⁴ A