A solenoid with 500 turns,0.10 m long,carrying a current of 2.0 A and with a radius of 10−² m will have what strength magnetic field at its center? (magnetic permeability in empty space µ₀ = 4π × 10−⁷ T⋅m/A) A) 31 × 10−⁴ T B) 1.3 × 10−² T C) 2.5 × 10−² T D) 62 × 10−⁴ T

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = µ₀ * (N/L) * I, where N is the number of turns, L is the length, and I is the current. Substituting the given values: B = (4π × 10⁻⁷ T⋅m/A) * (500/0.10 m) * 2.0 A = 1.3 × 10⁻² T.

A Solenoid with 500 Turns,0