The rate of heat dissipation in an AC circuit with resistance,R,and effective current,I_rms,is given by which of the following? A) 0.5 × (I_rms)²R B) (I_rms)²R C) 2.0 × (I_rms)²R D) 4.0 × (I_rms)²R

Question

Quizplus · Accepted Answer

The rate of heat dissipation in an AC circuit can be calculated using the formula P=I^2R, where P is the power dissipated, I is the effective current, and R is the resistance of the circuit. Using the formula for calculating the effective current of an AC circuit, we have: I = I_rms/sqrt(2) So, I^2 = I_rms^2/2 Substituting this in the formula for power, we get: P = (I_rms^2/2) * R = (I_rms^2 * R)/2 = (I_rms^2 * R)/(2*V_rms^2/R) = I_rms^2 * R/(2*V_rms^2/R) = (I_rms^2 * R)/(2*R^2) = I_rms^2/(2R) Therefore, the rate of heat dissipation in the given AC circuit is (I_rms)²R or option B.

The Rate of Heat Dissipation in an AC Circuit with Resistance,R,and