An AC voltage source,with a peak output of 309 V,is connected to a 80.0-Ω resistor.What is the effective (or rms)current in the circuit?
A) 2.73 A
B) 1.93 A
C) 3.86 A
D) 5.46 A
E) 7.73 A

Question

An AC voltage source,with a peak output of 309 V,is connected to a 80.0-Ω resistor.What is the effective (or rms)current in the circuit?
A) 2.73 A
B) 1.93 A
C) 3.86 A
D) 5.46 A
E) ​7.73 A

Quizplus · Accepted Answer

The effective (or rms) current in an AC circuit is given by the peak current divided by the square root of 2. In this case, the peak current is 309 V / 80.0 Ω = 3.86 A, so the effective current is 3.86 A / √2 = 2.73 A.

An AC Voltage Source,with a Peak Output of 309 V,is