A light source simultaneously emits light of two wavelengths,480 nm and 560 nm,respectively.The source is used in a double-slit interference experiment where the slit spacing is a 0.040 mm,and the distance between double slits and the screen is 1.6 m.What is the separation between the m = 3 bright fringes of the two wavelengths as they appear on the screen? (1 nm = 10−⁹ m)

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Quizplus · Accepted Answer

The separation between the m = 3 bright fringes for two wavelengths can be calculated using the formula for fringe separation: Δy = (m * λ * L) / d. For λ = 480 nm and λ = 560 nm, calculate Δy for each and find the difference. The separation is 0.96 cm.

A Light Source Simultaneously Emits Light of Two Wavelengths,480 Nm