Question 1

A surface is coated with a material having index of refraction 1.50.If light in air has a wavelength of 450 nm and is normally incident on this surface,and it is found through interference effects with this light that the surface is 15 wavelengths thick,which of the following is the thickness of the surface?

Accepted Answer

The answer of A surface is coated with a material...

Question 2

If a wave from one slit of a Young's double-slit set-up arrives at a point on the screen one-half wavelength behind the wave from the other slit,what is observed at that point?

Accepted Answer

When the waves from two slits are out of phase (one-half wavelength apart), they cancel each other out and produce a dark fringe on the screen.

Question 3

Light of wavelength 610 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 2.0 m from the slit.What is the distance of the second dark fringe from the center of the central bright fringe? (1 nm = 10−⁹ m)

Accepted Answer

The answer of Light of wavelength 610 nm is incident...

Question 4

A thin film ( 
)of thickness 77.6 nm,applied to a camera lens ( 
),is the minimum thickness that results in destructive interference for reflected light of wavelength 450 nm.which of the following is the next greater thickness that will also give destructive interference for this wavelength?

Accepted Answer

For destructive interference to occur, the reflected waves from the two surfaces of the thin film must be out of phase by half a wavelength (λ/2). The condition for this is:

2nt = (m + 1/2)λ

where n is the refractive index of the film, t is the thickness of the film, m is an integer (0,1,2,...) representing the order of the interference fringes.

For the given situation, m = 0 (minimum thickness for destructive interference), λ = 450 nm, and n = 1.5 (assumed for illustration purpose).

2 x 1.5 x 77.6 x 10^-9 m = (0 + 1/2) x 450 x 10^-9 m
=> t = 155.2 nm

Therefore, the next greater thickness that will also give destructive interference for this wavelength is 155 nm, which corresponds to option D.

Question 5

Light of wavelength 540 nm is incident on a slit of width 0.150 mm,and a diffraction pattern is produced on a screen that is 3.00 m from the slit.What is the width of the central bright fringe? (1 nm = 10−⁹ m)

Accepted Answer

The answer of Light of wavelength 540 nm is incident...

Question 6

Laser light sent through a double slit produces an interference pattern on a screen 3.00 m from the slits.If the m = 2 maximum occurs at an angle of 10.7°,at what angle does the m = 8 maximum occur?

Accepted Answer

The angle for the mth maximum is given by:sin θm = mλ/dwhere m is the order of the maximum, λ is the wavelength of the light, and d is the distance between the slits.For the m = 2 maximum, we have:sin 10.7° = 2λ/dFor the m = 8 maximum, we have:sin θ8 = 8λ/dDividing the second equation by the first equation, we get:sin θ8/sin 10.7° = 8/2 = 4Therefore, θ8 = 4 * 10.7° = 48.0°.

Question 7

A Young's interference experiment is conducted with blue-green argon laser light (λ = 515 nm).The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 4.95 m away.What is the spacing between the bright fringes? (1 nm = 10−⁹ m)

Accepted Answer

The spacing between the bright fringes can be calculated using the formula:

y = (mλD) / d

where y is the spacing between the bright fringes, m is the order of the fringe (m=0,1,2,...), λ is the wavelength of the light, D is the distance between the slits and the screen, and d is the separation between the slits.

Plugging in the values given in the problem, we get:

y = (0)(515 nm)(4.95 m) / 0.50 mm
y = 5.1 mm

Therefore, the spacing between the bright fringes is 5.1 mm. The correct answer is B.

Question 8

That all points on a wave front act as new sources of spherical waves is attributed to:

Accepted Answer

This statement is known as Huygens' principle and is attributed to Dutch physicist Christiaan Huygens.

Question 9

A light source simultaneously emits light of two wavelengths,480 nm and 560 nm,respectively.The source is used in a double-slit interference experiment where the slit spacing is a 0.040 mm,and the distance between double slits and the screen is 1.6 m.What is the separation between the m = 3 bright fringes of the two wavelengths as they appear on the screen? (1 nm = 10−⁹ m)

Accepted Answer

The separation between the m = 3 bright fringes for two wavelengths can be calculated using the formula for fringe separation: Δy = (m * λ * L) / d. For λ = 480 nm and λ = 560 nm, calculate Δy for each and find the difference. The separation is 0.96 cm.

Question 10

Two narrow slits are 0.025 mm apart.When a laser shines on them,bright fringes form on a screen that is a meter away.These fringes are 1.3 cm apart.What is the separation between the m = 2 bright fringe and the central fringe?

Accepted Answer

The separation between bright fringes is 1.3 cm. The m = 2 bright fringe is two fringe spacings away from the central fringe, so the separation is 2 * 1.3 cm = 2.6 cm.

Question 11

In a Young's double-slit experiment,how many maxima occur between the m = +3 and m = −3 maxima?

Accepted Answer

The answer of In a Young's double-slit experiment,how many maxima...

Question 12

A Young's double-slit apparatus is set up.The source wavelength is 430 nm,and the double-slit spacing is 0.040 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.6 cm? (1 nm = 10−⁹ m)

Accepted Answer

The spacing of the fringes can be calculated using the formula:

Dλ/d = y/D

where:
D = distance from the slits to the screen
λ = wavelength of the light
d = spacing of the double slits
y = distance from the central maximum to the nth fringe

Rearranging the equation, we get:

D = yd/λ

Plugging in the given values, we have:

y = 2.6 cm = 0.026 m
d = 0.040 mm = 4.0 x 10^-5 m
λ = 430 nm = 4.3 x 10^-7 m

D = (0.026 x 4.0 x 10^-5)/4.3 x 10^-7
D = 2.42 m

Therefore, the distance from the double slits to the screen should be approximately 2.4 m for the spacing between alternating bright fringes to be 2.6 cm. Answer B) is the best choice.

Question 13

A Young's double-slit apparatus is set up.A screen is positioned 1.16 m from the double slits,and the spacing between the two slits is 0.0500 mm.The distance between alternating bright fringes is 1.42 cm.What is the light source wavelength? (1 nm = 10−⁹ m)

Accepted Answer

The wavelength of light can be calculated using the formula for fringe spacing in a double-slit experiment: $ \Delta y = \frac{\lambda L}{d} $. Here, $\Delta y = 1.42 \times 10^{-2} \, \text{m}$, $L = 1.16 \, \text{m}$, and $d = 0.0500 \times 10^{-3} \, \text{m}$. Solving for $\lambda$, we get $\lambda = \frac{\Delta y \cdot d}{L} = \frac{1.42 \times 10^{-2} \cdot 0.0500 \times 10^{-3}}{1.16} \approx 6.12 \times 10^{-7} \, \text{m} = 612 \, \text{nm}$.

Question 14

In a Young's double-slit interference apparatus,the distance from the slits to the screen is tripled.The distance between adjacent light and dark fringes changes by a factor of:

Accepted Answer

The distance between adjacent fringes in Young's double-slit interference pattern depends on the wavelength of light used and the distance between the slits and the screen (known as the "path difference"). The path difference is given by d sin θ, where d is the distance between the slits and θ is the angle between the screen and the line connecting the slits and the point on the screen. When the distance from the slits to the screen is tripled, the path difference also triples. Since the distance between adjacent fringes is directly proportional to the path difference, the distance between adjacent fringes also triples. Therefore, the correct answer is C.

Question 15

In a Young's double-slit experiment,by how many wavelengths do the paths from the slits to the screen differ for the m = 3 and the m = 8 minima?

Accepted Answer

The path difference in a Young's double-slit experiment is given by d sin(theta), where d is the distance between the slits and theta is the angle between the incident light and the line from the slits to the point on the screen. For the m=3 minimum, we have sin(theta) = (m lambda)/d = (3 lambda)/d, where lambda is the wavelength of the light used. For the m=8 minimum, we have sin(theta) = (8 lambda)/d. The difference between the two path differences is given by:

d sin(theta)_8 - d sin(theta)_3 = d (8 lambda)/d - d (3 lambda)/d = 5 lambda

So the paths from the slits to the screen differ by 5 wavelengths for the m=3 and m=8 minima. Therefore, the best answer is C) 5.

Question 16

In a Young's double-slit experiment,both the wavelength and the slit separation are increased by 25%.What happens to the distance between two adjacent bright fringes?

Accepted Answer

The distance between adjacent bright fringes in a Young's double-slit experiment is given by dλ/D where d is the slit separation, λ is the wavelength, and D is the distance between the slits and the screen. If both λ and d are increased by 25%, then the distance between adjacent bright fringes will remain the same because the ratio of dλ/D is unchanged.

Question 17

A Young's double-slit apparatus is set up so that a screen is positioned 1.6 m from the double slits,and the spacing between the two slits is 0.0315 mm.What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 630 nm? (1 nm = 10−⁹ m)

Accepted Answer

The answer of A Young's double-slit apparatus is set up...

Question 18

In a Young's double-slit interference apparatus,by what factor is the distance between adjacent light and dark fringes changed when the separation between slits is tripled?

Accepted Answer

The fringe spacing in a double-slit experiment is inversely proportional to the slit separation. Tripling the slit separation reduces the fringe spacing by a factor of 1/3.

Question 19

A silicon monoxide (n = 1.45)film of 108 nm thickness is used to coat a glass camera lens (n = 1.56).What wavelength of light in the visible region (390 to 710 nm)will be most efficiently transmitted by this system? (1 nm = 10−⁹ m)

Accepted Answer

The answer of A silicon monoxide (n = 1.45)film of...

Question 20

A Young's double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits.If the distance between alternating bright fringes is 0.83 cm,and the light source has a wavelength of 580 nm,what is the separation of the double slits? (1 nm = 10−⁹ m)

Accepted Answer

The answer of A Young's double-slit apparatus is set up...

Quiz 25: Optical Instruments: Part A

If a wave from one slit of a Young's double-slit set-up arrives at a point on the screen one-half wavelength behind the wave from the other slit,what is observed at that point?

Light of wavelength 610 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 2.0 m from the slit.What is the distance of the second dark fringe from the center of the central bright fringe? (1 nm = 10−⁹ m)

A thin film ( ) of thickness 77.6 nm,applied to a camera lens ( ) ,is the minimum thickness that results in destructive interference for reflected light of wavelength 450 nm.which of the following is the next greater thickness that will also give destructive interference for this wavelength?

Light of wavelength 540 nm is incident on a slit of width 0.150 mm,and a diffraction pattern is produced on a screen that is 3.00 m from the slit.What is the width of the central bright fringe? (1 nm = 10−⁹ m)

Laser light sent through a double slit produces an interference pattern on a screen 3.00 m from the slits.If the m = 2 maximum occurs at an angle of 10.7°,at what angle does the m = 8 maximum occur?

A Young's interference experiment is conducted with blue-green argon laser light (λ = 515 nm) .The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 4.95 m away.What is the spacing between the bright fringes? (1 nm = 10−⁹ m)

That all points on a wave front act as new sources of spherical waves is attributed to:

Two narrow slits are 0.025 mm apart.When a laser shines on them,bright fringes form on a screen that is a meter away.These fringes are 1.3 cm apart.What is the separation between the m = 2 bright fringe and the central fringe?

In a Young's double-slit experiment,how many maxima occur between the m = +3 and m = −3 maxima?

A Young's double-slit apparatus is set up.The source wavelength is 430 nm,and the double-slit spacing is 0.040 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.6 cm? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up.A screen is positioned 1.16 m from the double slits,and the spacing between the two slits is 0.0500 mm.The distance between alternating bright fringes is 1.42 cm.What is the light source wavelength? (1 nm = 10−⁹ m)

In a Young's double-slit interference apparatus,the distance from the slits to the screen is tripled.The distance between adjacent light and dark fringes changes by a factor of:

In a Young's double-slit experiment,by how many wavelengths do the paths from the slits to the screen differ for the m = 3 and the m = 8 minima?

In a Young's double-slit experiment,both the wavelength and the slit separation are increased by 25%.What happens to the distance between two adjacent bright fringes?

A Young's double-slit apparatus is set up so that a screen is positioned 1.6 m from the double slits,and the spacing between the two slits is 0.0315 mm.What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 630 nm? (1 nm = 10−⁹ m)

In a Young's double-slit interference apparatus,by what factor is the distance between adjacent light and dark fringes changed when the separation between slits is tripled?

A silicon monoxide (n = 1.45) film of 108 nm thickness is used to coat a glass camera lens (n = 1.56) .What wavelength of light in the visible region (390 to 710 nm) will be most efficiently transmitted by this system? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits.If the distance between alternating bright fringes is 0.83 cm,and the light source has a wavelength of 580 nm,what is the separation of the double slits? (1 nm = 10−⁹ m)

Quiz 25: Optical Instruments: Part A

If a wave from one slit of a Young's double-slit set-up arrives at a point on the screen one-half wavelength behind the wave from the other slit,what is observed at that point?

Light of wavelength 610 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 2.0 m from the slit.What is the distance of the second dark fringe from the center of the central bright fringe? (1 nm = 10−9 m)

A thin film ( ) of thickness 77.6 nm,applied to a camera lens ( ) ,is the minimum thickness that results in destructive interference for reflected light of wavelength 450 nm.which of the following is the next greater thickness that will also give destructive interference for this wavelength?

Light of wavelength 540 nm is incident on a slit of width 0.150 mm,and a diffraction pattern is produced on a screen that is 3.00 m from the slit.What is the width of the central bright fringe? (1 nm = 10−9 m)

Laser light sent through a double slit produces an interference pattern on a screen 3.00 m from the slits.If the m = 2 maximum occurs at an angle of 10.7°,at what angle does the m = 8 maximum occur?

A Young's interference experiment is conducted with blue-green argon laser light (λ = 515 nm) .The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 4.95 m away.What is the spacing between the bright fringes? (1 nm = 10−9 m)

That all points on a wave front act as new sources of spherical waves is attributed to:

Two narrow slits are 0.025 mm apart.When a laser shines on them,bright fringes form on a screen that is a meter away.These fringes are 1.3 cm apart.What is the separation between the m = 2 bright fringe and the central fringe?

In a Young's double-slit experiment,how many maxima occur between the m = +3 and m = −3 maxima?

A Young's double-slit apparatus is set up.The source wavelength is 430 nm,and the double-slit spacing is 0.040 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.6 cm? (1 nm = 10−9 m)

A Young's double-slit apparatus is set up.A screen is positioned 1.16 m from the double slits,and the spacing between the two slits is 0.0500 mm.The distance between alternating bright fringes is 1.42 cm.What is the light source wavelength? (1 nm = 10−9 m)

In a Young's double-slit interference apparatus,the distance from the slits to the screen is tripled.The distance between adjacent light and dark fringes changes by a factor of:

In a Young's double-slit experiment,by how many wavelengths do the paths from the slits to the screen differ for the m = 3 and the m = 8 minima?

In a Young's double-slit experiment,both the wavelength and the slit separation are increased by 25%.What happens to the distance between two adjacent bright fringes?

A Young's double-slit apparatus is set up so that a screen is positioned 1.6 m from the double slits,and the spacing between the two slits is 0.0315 mm.What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 630 nm? (1 nm = 10−9 m)

In a Young's double-slit interference apparatus,by what factor is the distance between adjacent light and dark fringes changed when the separation between slits is tripled?

A silicon monoxide (n = 1.45) film of 108 nm thickness is used to coat a glass camera lens (n = 1.56) .What wavelength of light in the visible region (390 to 710 nm) will be most efficiently transmitted by this system? (1 nm = 10−9 m)

A Young's double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits.If the distance between alternating bright fringes is 0.83 cm,and the light source has a wavelength of 580 nm,what is the separation of the double slits? (1 nm = 10−9 m)

Light of wavelength 610 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 2.0 m from the slit.What is the distance of the second dark fringe from the center of the central bright fringe? (1 nm = 10−⁹ m)

Light of wavelength 540 nm is incident on a slit of width 0.150 mm,and a diffraction pattern is produced on a screen that is 3.00 m from the slit.What is the width of the central bright fringe? (1 nm = 10−⁹ m)

A Young's interference experiment is conducted with blue-green argon laser light (λ = 515 nm) .The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 4.95 m away.What is the spacing between the bright fringes? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up.The source wavelength is 430 nm,and the double-slit spacing is 0.040 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.6 cm? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up.A screen is positioned 1.16 m from the double slits,and the spacing between the two slits is 0.0500 mm.The distance between alternating bright fringes is 1.42 cm.What is the light source wavelength? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up so that a screen is positioned 1.6 m from the double slits,and the spacing between the two slits is 0.0315 mm.What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 630 nm? (1 nm = 10−⁹ m)

A silicon monoxide (n = 1.45) film of 108 nm thickness is used to coat a glass camera lens (n = 1.56) .What wavelength of light in the visible region (390 to 710 nm) will be most efficiently transmitted by this system? (1 nm = 10−⁹ m)

A Young's double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits.If the distance between alternating bright fringes is 0.83 cm,and the light source has a wavelength of 580 nm,what is the separation of the double slits? (1 nm = 10−⁹ m)