The red light from a HeNe laboratory laser results from a transition in Ne.Determine the energy difference between the states if the wavelength of the light given off is 634 nm.(h = 6.63 × 10−³⁴ J⋅s,c = 3.00 × 10⁸ m/s,1 eV = 1.60 × 10−¹⁹ J,and 1 nm = 10−⁹ m) A) 2.22 eV B) 1.43 eV C) 1.96 eV D) 2.04 eV

Question

Quizplus · Accepted Answer

The energy difference can be calculated using the formula E = hc/λ. Substituting the given values, E = (6.63 × 10^-34 J⋅s)(3.00 × 10^8 m/s) / (634 × 10^-9 m) = 3.14 × 10^-19 J. Converting to eV, E = (3.14 × 10^-19 J) / (1.60 × 10^-19 J/eV) = 1.96 eV.

The Red Light from a HeNe Laboratory Laser Results from a Transition