What mass of phosphorus pentafluoride,PF₅,has the same number of fluorine atoms as 25.0 g of oxygen difluoride,OF₂?

Question

Quizplus · Accepted Answer

First, we need to determine the number of fluorine atoms in 25.0 g of OF2:

25.0 g OF2 x (1 mol OF2/53.996 g OF2) x (2 F atoms/1 mol OF2) = 0.926 mol F atoms

Next, we need to convert this number of fluorine atoms to the number of moles of PF5:

0.926 mol F atoms x (1 mol PF5/5 mol F atoms) = 0.185 mol PF5

Finally, we can calculate the mass of PF5 that contains this many moles:

0.185 mol PF5 x 125.96 g/mol PF5 = 23.3 g PF5

Therefore, the answer is C (23.3 g).

What Mass of Phosphorus Pentafluoride,PF5,has the Same Number of Fluorine