Iron metal reacts with chlorine gas as follows:
2 Fe(s) + 3 Cl₂(g) → 2 FeCl₃(s)
How many moles of FeCl₃ are obtained when 4.6 mol of Cl₂ reacts with excess Fe?

Question

Iron metal reacts with chlorine gas as follows: 2 Fe(s)+ 3 Cl₂(g)→ 2 FeCl₃(s) How many moles of FeCl₃ are obtained when 4.6 mol of Cl₂ reacts with excess Fe?

Quizplus · Accepted Answer

According to the balanced chemical equation, 3 moles of Cl₂ react to produce 2 moles of FeCl₃. Therefore, 4.6 moles of Cl₂ would produce (4.6 moles Cl₂ * 2 moles FeCl₃ / 3 moles Cl₂) = 3.1 moles of FeCl₃.

Iron Metal Reacts with Chlorine Gas as Follows