If 0.500 mol of CaCl₂ is mixed with 0.200 mol Na₃PO₄,the maximum amount in moles of Ca₃(PO₄)₂ that can be formed is 0.10 moles.Calculate the extent of reaction ,x. A)0.2 B)0.10 C)0.35 D)0 E)0.65

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Quizplus · Accepted Answer

The extent of reaction, $x$, is calculated based on the stoichiometry of the reaction and the limiting reactant. Given that 0.10 moles of $Ca^{13}PO_4^{12}$ can be formed, it indicates that the reaction proceeded to an extent where 0.10 moles of the product were formed from the limiting reactant. Since the formation of $Ca^{13}PO_4^{12}$ directly relates to the amount of reactant consumed, and given the stoichiometry of the reaction (which is not explicitly provided but implied to be 1:1 for the formation of the product), $x = 0.10$ moles represents the extent of reaction, indicating how much of the reactants have reacted.

If 0500 Mol of CaCl2 Is Mixed with 0

If 0500 Mol of CaCl₂ Is Mixed with 0