If an aqueous solution containing 46 g of sodium carbonate per liter is mixed with an equal volume of 0.20 M aqueous hydrochloric acid,what would be the molarity of sodium chloride in the final solution,assuming volumes were additive?
A)0.10 M
B)0.20 M
C)0.22 M
D)0.43 M
E)0.50 M

Question

Quizplus · Accepted Answer

The correct answer is A because the molarity of sodium chloride in the final solution is 0.10 M. This is because the sodium carbonate and hydrochloric acid react in a 1:2 ratio, so the final solution will contain half of the original amount of sodium carbonate and all of the original amount of hydrochloric acid. The molarity of sodium chloride in the final solution will therefore be 0.10 M.

If an Aqueous Solution Containing 46 G of Sodium Carbonate