You have 10.00 L of a 0.350 M KCl solution,but you need a solution that is 0.450 M.What volume of water,in L,would you evaporate from the solution?
A)4.38 L
B)3.50 L
C)2.85 L
D)7.77 L
E)2.22 L

Question

Quizplus · Accepted Answer

To concentrate a solution from 0.350 M to 0.450 M without adding more solute, you need to evaporate some of the solvent. The amount of KCl in the original solution is the volume times the concentration, which is $10.00 \, \text{L} \times 0.350 \, \text{M} = 3.50 \, \text{mol}$. To achieve a concentration of 0.450 M with the same amount of KCl, you can set up the equation $3.50 \, \text{mol} = 0.450 \, \text{M} \times V$, where $V$ is the final volume of the solution. Solving for $V$ gives $V = \frac{3.50}{0.450} = 7.78 \, \text{L}$. To find the volume of water evaporated, subtract the final volume from the initial volume: $10.00 \, \text{L} - 7.78 \, \text{L} = 2.22 \, \text{L}$.

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