What mass of MgCl₂ in grams must be added to 250.0 mL of a 0.25 M MgCl₂ solution to produce a 0.40 M solution,assuming no change of volume upon addition? A)9.5 g B)6.0 g C)2.2 g D)3.6 g E)19 g

Question

Quizplus · Accepted Answer

Use the formula: M1V1 = M2V2 Rearrange to solve for V2, the volume of the 0.40 M solution to be produced: V2 = M1V1/M2 = (0.25 M)(250.0 mL)/(0.40 M) = 156.25 mL This is the volume of the final solution. To find the mass of MgCl₂ needed, use the formula: mass = moles x molar mass First, calculate the number of moles needed in the final solution: moles = M x L = (0.40 M)(156.25 mL/1000 mL) = 0.0625 moles Next, calculate the mass of MgCl₂ needed: mass = moles x molar mass = (0.0625 moles)(95.211 g/mol) = 5.95 g Therefore, the closest answer choice is D) 3.6 g.

What Mass of MgCl2 in Grams Must Be Added to 250.0

What Mass of MgCl₂ in Grams Must Be Added to 250.0