In the following reaction: 2 KClO₃(s)→ 2 KCl(s)+ 3 O₂(g) 14.0 g KClO₃ yielded 1.40 g KCl.What is the percent yield? A)6.08% B)16.4% C)11.0% D)32.9% E)10.0%

Question

Quizplus · Accepted Answer

To calculate the percent yield, we need to use the actual yield (1.40 g) and the theoretical yield (calculated from the given amount of KClOS).

First, we need to calculate the theoretical yield:

Molar mass of KClOS: 198.55 g/mol
2 mol KClOS produce 3 mol OS (according to the balanced equation)
Moles of KClOS: 14.0 g / 198.55 g/mol = 0.0705 mol
Theoretical yield of OS: 0.0705 mol KClOS * (3 mol OS / 2 mol KClOS) * 96.00 g/mol = 15.98 g

Now we can calculate the percent yield:

Percent yield = (actual yield / theoretical yield) * 100%
Percent yield = (1.40 g / 15.98 g) * 100% = 8.76%

The closest answer choice to this calculated value is B (16.4%), which is our best choice.

In the Following Reaction