Sodium metal and water react to form hydrogen and sodium hydroxide.If 5.98 g of sodium react with water to form 0.26 g of hydrogen and 10.40 g of sodium hydroxide,what mass of water was involved in the reaction?
A)4.68 g
B)5.98 g
C)10.14 g
D)10.66 g

Question

Quizplus · Accepted Answer

The mass of water involved can be found using the law of conservation of mass. The total mass before the reaction (sodium + water) equals the total mass after the reaction (hydrogen + sodium hydroxide). The mass of sodium is given as 5.98 g, and the masses of hydrogen and sodium hydroxide produced are 0.26 g and 10.40 g, respectively. The total mass after the reaction is 0.26 g + 10.40 g = 10.66 g. To find the mass of water, subtract the mass of sodium from the total mass after the reaction: 10.66 g - 5.98 g = 4.68 g.

Sodium Metal and Water React to Form Hydrogen and Sodium