What is the concentration of FeCl₃ in a solution prepared by dissolving 20.0 g of FeCl₃ in enough water to make 275 mL of solution? A)4.48 × 10^-4 mol L^-1 B)0.448 mol L^-1 C)2.23 mol L^-1 D)2.23 × 10³ mol L^-1

Question

Quizplus · Accepted Answer

We need to use the formula: concentration (in mol/L) = (mass of solute in grams / molar mass of solute) / volume of solution in L First, we need to convert the given volume to L: 275 mL = 275/1000 L = 0.275 L Next, we need the molar mass of FeCl₃, which is: Fe: 1 x 55.85 g/mol = 55.85 g/mol Cl: 1 x 35.45 g/mol = 35.45 g/mol Total: 55.85 + 35.45 = 91.30 g/mol Now we can plug in the values: concentration (in mol/L) = (20.0 g / 91.30 g/mol) / 0.275 L concentration (in mol/L) = 0.248 mol/L So the answer is B, 0.448 mol/L.

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