If 250.L of nitrogen reacts with 582 L of hydrogen by the reaction:
N₂(g) + 3 H₂(g) → 2 NH₃(g) ,
How much nitrogen is unreacted? All gases are at the same temperature and pressure.

Question

If 250.L of nitrogen reacts with 582 L of hydrogen by the reaction: N₂(g)+ 3 H₂(g)→ 2 NH₃(g), How much nitrogen is unreacted? All gases are at the same temperature and pressure.

Quizplus · Accepted Answer

The reaction shows that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Given the volumes of nitrogen and hydrogen, we can use the stoichiometry of the reaction to find the unreacted nitrogen. Since all gases are at the same temperature and pressure, their volumes are directly proportional to the moles. The limiting reactant is hydrogen (582 L divided by 3 = 194 L of nitrogen required). Since 250 L of nitrogen was initially present, 250 L - 194 L = 56 L of nitrogen remains unreacted.

If 250L of Nitrogen Reacts with 582 L of Hydrogen by by the Reaction