How much heat is needed to raise the temperature of 5.28 gal of water from 25.0 °C to 88.0 °C(1 gal = 3.785 L)?

Question

Quizplus · Accepted Answer

First, we need to convert gallons to liters: 
5.28 gal x 3.785 L/gal = 19.9788 L

Then, we can use the formula: 
q = m·c·ΔT
where q is the heat needed, m is the mass of the water (in kg), c is the specific heat of water (4.184 J/g·°C), and ΔT is the change in temperature (in °C).

Converting the mass from liters to kg: 
19.9788 L x 1 kg/1000 L = 0.0199788 kg

ΔT = (88.0 °C - 25.0 °C) = 63.0 °C

Plugging in the values: 
q = 0.0199788 kg x 4.184 J/g·°C x 63.0 °C = 5260 J = 5.260 kJ

Therefore, the answer is A)5260 kJ.

How Much Heat Is Needed to Raise the Temperature of 5.28