1674 J of heat are absorbed by 25.0 mL of NaOH (d = 1.10 g/mL,specific heat = 4.10 J/g °C).The temperature of the NaOH goes up by how many degrees?

Question

Quizplus · Accepted Answer

To find the temperature change, use the formula $q = mc\Delta T$, where $q$ is the heat absorbed, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the temperature change. First, find the mass of NaOH: $25.0 \, \text{mL} \times 1.10 \, \text{g/mL} = 27.5 \, \text{g}$. Then, rearrange the formula to solve for $\Delta T$: $\Delta T = \frac{q}{mc} = \frac{1674 \, \text{J}}{27.5 \, \text{g} \times 4.10 \, \text{J/g}^\circ\text{C}} = 14.8^\circ\text{C}$.

1674 J of Heat Are Absorbed by 25