At 1.0133 bar,the heat of sublimation of gallium is 277 kJ mol^-1 And the heat of vaporization is 271 kJ mol^-1 .To the correct number of significant figures,how much heat is required to melt 5.50 mol of gallium at 1.0133 bar?

Question

Quizplus · Accepted Answer

The heat of sublimation is the sum of the heat of fusion (melting) and the heat of vaporization. Therefore, to find the heat of fusion, subtract the heat of vaporization from the heat of sublimation: 277 kJ/mol - 271 kJ/mol = 6 kJ/mol. For 5.50 mol, the heat required to melt gallium is 5.50 mol * 6 kJ/mol = 33 kJ.

At 10133 Bar,the Heat of Sublimation of Gallium Is 277 KJ