For the reaction below CO(g)+ 2 H₂(g)⇌ CH₃OH(g) The equilibrium concentrations at 483 K are [CO] = 0.0753 M,[H₂] = 0.151 M,and [CH₃OH] = 0.0247 M.Calculate the value of K_c.

Question

Quizplus · Accepted Answer

The equilibrium constant, Kc, is calculated using the equilibrium concentrations of the reactants and products. The expression for Kc is:Kc = [CH3OH]/[CO][H2]^2Substituting the given equilibrium concentrations into the expression, we get:Kc = (0.0247 M)/(0.0753 M)(0.151 M)^2 = 14.4Therefore, the value of Kc is 14.4.

For the Reaction Below