Two moles of NH₃ are initially present for the reaction:
2 NH₃(g) ⇌ N₂(g) + 3 H₂(g)
At equilibrium there is 1.00 mol NH₃.How many moles of H₂ are present at equilibrium?

Question

Two moles of NH₃ are initially present for the reaction: 2 NH₃(g)⇌ N₂(g)+ 3 H₂(g) At equilibrium there is 1.00 mol NH₃.How many moles of H₂ are present at equilibrium?

Quizplus · Accepted Answer

At equilibrium, using the stoichiometric coefficients from the balanced reaction, we can conclude that 3 moles of H₂ are formed for every 2 moles of NH₃ that react. Therefore, if 2 moles of NH₃ initially react, we can expect 3/2 times as many moles of H₂ to form, which is equal to 1.5 moles. Thus, the correct answer is (C).

Two Moles of NH3 Are Initially Present for the Reaction

Two Moles of NH₃ Are Initially Present for the Reaction