In the reaction: 2 N₂O(g)+ N₂H₄(g)⇌ 3 N₂(g)+ 2 H₂O(g), One starts with 0.10 mol N₂O and 0.25 mol N₂H₄ in a 10.0 L container.If there are 0.06 mol N₂O at equilibrium,how many moles of N₂ are present?

Question

Quizplus · Accepted Answer

Since the reaction is in equilibrium, we can set up an ICE (initial, change, equilibrium) table to determine the amount of N₂ at equilibrium: | | N₂O | N₂H₄ | N₂ | |-------|----------------|-----------------------------|----------------| | I | 0.10 mol | 0.25 mol | 0 | | C | -0.04 mol | -0.08 mol | +0.06 mol | | E | 0.06 mol | 0.17 mol | 0.06 mol | We can see from the table that the amount of N₂ at equilibrium is 0.06 mol. Therefore, the answer is C) 0.06 mol.

In the Reaction: 2 N2O(g)+ N2H4(g)⇌ 3 N2(g)+ 2 H2O(g)

In the Reaction: 2 N₂O(g)+ N₂H₄(g)⇌ 3 N₂(g)+ 2 H₂O(g)