The For the reaction below is 1.49 × 10⁸ at 100.0 °C:
CO(g) +Cl₂(g) →COCl(g)
In an equilibrium mixture of the three gases, P_CO=P_Cl₂= 2.22 × 10^-4 bar.The partial pressure of the product,phosgene ( COCl₂) ,is ________ bar.

Question

The

The For the reaction below is 1.49 × 10<sup>8</sup> at 100.0 °C: CO(g) +Cl<sub>2</sub>(g) →COCl(g) In an equilibrium mixture of the three gases, P<sub>CO</sub>=P<sub>Cl<sub>2</sub></sub>= 2.22 × 10<sup>-4</sup> bar.The partial pressure of the product,phosgene ( COCl<sub>2</sub>) ,is ________ bar. A) 7.34 B) 3.02 × 10<sup>15</sup> C) 3.31 × 10<sup>-16</sup> D) 3.31 × 10<sup>4</sup> E) 6.67 × 10<sup>11</sup>

For the reaction below is 1.49 × 10⁸ at 100.0 °C:
CO(g) +Cl₂(g) →COCl(g)
In an equilibrium mixture of the three gases, P_CO=P_Cl₂= 2.22 × 10^-4 bar.The partial pressure of the product,phosgene ( COCl₂) ,is ________ bar.

Quizplus · Accepted Answer

The Answer of The For the reaction below is 1.49 × 10⁸ at 100.0 °C: CO(g)+Cl₂(g)→COCl(g) In an equilibrium mixture of the three gases, P_CO=P_Cl₂= 2.22 × 10^-4 bar.The partial pressure of the product,phosgene ( COCl₂),is ________ bar.

The for the Reaction Below Is 1