At 900.0 K,the equilibrium constant (K_p) for the following reaction is 0.345:
+ (g) → (g)
At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar.

Question

At 900.0 K,the equilibrium constant (K_p) for the following reaction is 0.345:

At 900.0 K,the equilibrium constant (K<sub>p</sub>) for the following reaction is 0.345: + (g) → (g) At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar. A) 82.0 B) 4.21 × C) 192 D) 6.20 × 10<sup>-4</sup> E) 40.2

+

(g) →

(g)
At equilibrium,the partial pressure of At 900.0 K,the equilibrium constant (Kp) for the following reaction is 0.345: + (g) → (g) At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar. A) 82.0 B) 4.21 × C) 192 D) 6.20 × 10-4 E) 40.2

Is 35.0 bar and that of At 900.0 K,the equilibrium constant (Kp) for the following reaction is 0.345: + (g) → (g) At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar. A) 82.0 B) 4.21 × C) 192 D) 6.20 × 10-4 E) 40.2

Is 15.9 bar.The partial pressure of At 900.0 K,the equilibrium constant (Kp) for the following reaction is 0.345: + (g) → (g) At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar. A) 82.0 B) 4.21 × C) 192 D) 6.20 × 10-4 E) 40.2

Is ________ bar.

Quizplus · Accepted Answer

The Answer of At 900.0 K,the equilibrium constant (K_p)for the following reaction is 0.345: + (g)→ (g) At equilibrium,the partial pressure of Is 35.0 bar and that of Is 15.9 bar.The partial pressure of Is ________ bar.

At 9000 K,the Equilibrium Constant (Kp)for the Following Reaction Is 0

At 9000 K,the Equilibrium Constant (K_p)for the Following Reaction Is 0