What volume of 5.00 × 10^-3 mol L^-1 HNO₃(aq)is needed to titrate 80.00 mL of 5.00 × 10^-3 mol L^-1 Ca(OH)₂(aq)to the equivalence point? A)10.0 mL B)40.0 mL C)80.0 mL D)160.mL

Question

Quizplus · Accepted Answer

The reaction between HNO3 and Ca(OH)2 is a neutralization reaction where 2 moles of HNO3 react with 1 mole of Ca(OH)2. Given the concentrations are the same (5.00 × 10^-3 mol/L), and the volume of Ca(OH)2 is 80.00 mL, the volume of HNO3 needed is double that of Ca(OH)2 to reach the equivalence point, hence 160 mL.

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