Find E_cell for the following voltaic cell at 25 °C:
Ti(s) ∣ Ti²⁺(aq) (0.550M) Sn²⁺(aq) (0.005 M) ∣ Sn(s)
The half-reactions are:
Ti²⁺(aq) + 2 e^- ⇔ Ti(s) E° = -1.630 V
Sn²⁺(aq) + 2 e^- ⇔ Sn(s) E° = -0.137 V

Question

Find E_cell for the following voltaic cell at 25 °C:
Ti(s) ∣ Ti²⁺(aq) (0.550M) Find Ecell for the following voltaic cell at 25 °C: Ti(s) ∣ Ti2+(aq) (0.550M) Sn2+(aq) (0.005 M) ∣ Sn(s) The half-reactions are: Ti2+(aq) + 2 e- ⇔ Ti(s) E° = -1.630 V Sn2+(aq) + 2 e- ⇔ Sn(s) E° = -0.137 V A) 1.372 V B) 1.707 V C) 1.646 V D) 1.433 V E) -1.646 V

Find E<sub>cell</sub> for the following voltaic cell at 25 °C: Ti(s) ∣ Ti<sup>2+</sup>(aq) (0.550M) Sn<sup>2+</sup>(aq) (0.005 M) ∣ Sn(s) The half-reactions are: Ti<sup>2+</sup>(aq) + 2 e<sup>-</sup> ⇔ Ti(s) E° = -1.630 V Sn<sup>2+</sup>(aq) + 2 e<sup>-</sup> ⇔ Sn(s) E° = -0.137 V A) 1.372 V B) 1.707 V C) 1.646 V D) 1.433 V E) -1.646 V

Sn²⁺(aq) (0.005 M) ∣ Sn(s)
The half-reactions are:
Ti²⁺(aq) + 2 e^- ⇔ Ti(s) E° = -1.630 V
Sn²⁺(aq) + 2 e^- ⇔ Sn(s) E° = -0.137 V

Quizplus · Accepted Answer

The Answer of Find E_cell for the following voltaic cell at 25 °C: Ti(s)∣ Ti²⁺(aq)(0.550M) Sn²⁺(aq)(0.005 M)∣ Sn(s) The half-reactions are: Ti²⁺(aq)+ 2 e^- ⇔ Ti(s)E° = -1.630 V Sn²⁺(aq)+ 2 e^- ⇔ Sn(s)E° = -0.137 V

Find Ecell for the Following Voltaic Cell at 25 °C

Find E_cell for the Following Voltaic Cell at 25 °C