What is Keq at 25 °C of the spontaneous cell made from the Zn²⁺(aq)/Zn(s)(-0.76 V)and Br₂(l)/2Br^-(aq)(1.07 V)half cells?

Name: What is Keq at 25 °C of the spontaneous cell made from the Zn 2+ (aq)/Zn(s)(-0.76 V)and Br 2 (l)/2Br - (aq)(1.07 V)half cells?
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Quizplus · Accepted Answer

The cell potential (E°cell) is calculated as 1.07 V - (-0.76 V) = 1.83 V. Using the Nernst equation, Keq = 10^(nE°cell/0.0592), where n = 2 for the balanced reaction. Thus, Keq = 10^(2*1.83/0.0592) ≈ 8 × 10^61.

What Is Keq at 25 °C of the Spontaneous Cell