The rate constant at 160 °C for the first order decomposition of ore is 0.032/min.The half-life of the reaction is ________.

Question

Quizplus · Accepted Answer

The half-life (t₁/₂) for a first-order reaction is calculated using the formula t₁/₂ = 0.693/k, where k is the rate constant. Substituting the given rate constant (0.032/min) into the formula gives t₁/₂ = 0.693/0.032 = 21.65625 minutes. Converting this to seconds (21.65625 * 60) gives approximately 1300 seconds.

The Rate Constant at 160 °C for the First Order