The first-order reaction,SO₂Cl₂ → SO₂ + Cl₂,has a rate constant equal to 2.20 × 10^-5 s^-1 at 593 K.What percentage of the initial amount of SO₂Cl₂ will remain after 6.00 hours?

Question

Quizplus · Accepted Answer

For a first-order reaction, the remaining concentration can be calculated using the formula: [A] = [A]₀e^(-kt). Converting 6 hours to seconds (6 × 3600 = 21600 s) and substituting the given values, the percentage remaining is approximately 62.2%.

The First-Order Reaction,SO2Cl2 → SO2 + Cl2,has a Rate Constant

The First-Order Reaction,SO₂Cl₂ → SO₂ + Cl₂,has a Rate Constant