If 10.6 moles of water at 35°C absorbs 12.30 kJ, what is the final temperature of the water? The specific heat of water is 4.184 J/g·°C.
A)15°C
B)20°C
C)35°C
D)50.°C
E)312°C

Question

Quizplus · Accepted Answer

To find the final temperature, use the formula q = m*c*ΔT. First, convert moles of water to grams (10.6 moles * 18.015 g/mol = 190.959 g). Convert 12.30 kJ to J (12.30 kJ * 1000 = 12300 J). Rearrange the formula to solve for ΔT: ΔT = q / (m*c). Plug in the values: ΔT = 12300 J / (190.959 g * 4.184 J/g°C) = 15°C. Add this to the initial temperature: 35°C + 15°C = 50°C.

If 106 Moles of Water at 35°C Absorbs 12