A beaker contains 115 g of ethanol at 18.2°C.If the ethanol absorbs 1125 J of heat without losing heat to the surroundings, what will be the final temperature of the ethanol? The specific heat of ethanol is 2.46 J/g.°C.
A)4.08°C
B)14.1°C
C)18.4°C
D)22.2°C
E)36.4°C

Question

Quizplus · Accepted Answer

Using the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of ethanol, c is the specific heat of ethanol, and ΔT is the change in temperature.

Rearranging for ΔT, we get ΔT = Q / (mc)

Plugging in the values, we get:
ΔT = (1125 J) / (115 g * 2.46 J/g°C) = 4.22°C

Therefore, the final temperature of the ethanol will be:
18.2°C + 4.22°C = 22.42°C

Rounding to the nearest tenth, we get:
22.2°C

Thus, the answer is D.

A Beaker Contains 115 G of Ethanol at 18