A 135 g sample of H₂O at 85°C is cooled.The water loses a total of 15 kJ of energy in the cooling process.What is the final temperature of the water? The specific heat of water is 4.184 J/g·°C. A)27°C B)58°C C)70°C D)84°C E)112°C

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Quizplus · Accepted Answer

The energy lost (15,000 J) is equal to the mass (135 g) times the specific heat (4.184 J/g°C) times the change in temperature (ΔT). Solving for ΔT gives ΔT = 15,000 J / (135 g * 4.184 J/g°C) = 26.7°C. The final temperature is 85°C - 26.7°C = 58.3°C, which rounds to 58°C.

A 135 G Sample of H2O at 85°C Is Cooled

A 135 G Sample of H₂O at 85°C Is Cooled