Consider the reaction N₂(g)+ O₂(g) 2NO(g), for which K_c = 0.10 at 2,000ºC.Starting with initial concentrations of 0.040 M of N₂ and 0.040 M of O₂, determine the equilibrium concentration of NO.

Question

Quizplus · Accepted Answer

First, we need to set up the equilibrium expression: K_c = [NO]2 / ([N₂][O₂]) Substitute the given values: 0.10 = [NO]2 / (0.040 M)2 Solve for [NO]: [NO]2 = 0.10 x (0.040 M)2 [NO]2 = 0.000064 [NO] = 0.008 Since we have two NO molecules in the balanced equation, we multiply by 2 to get the equilibrium concentration of NO: [NO]eq = 2 x 0.008 = 0.016 M, which is closest to choice C, 0.013 M.

Consider the Reaction N2(g)+ O2(g) 2NO(g), for Which

Consider the Reaction N₂(g)+ O₂(g) 2NO(g), for Which